If the circumference of a circle is equal to the perimeter of a square, and the radius of the given circle is positive, then which of the following options is correct? |
Area of the circle > Area of the square Area of the circle ≥ Area of the square Area of the circle < Area of the square Area of the circle = Area of the square |
Area of the circle > Area of the square |
We know that, Area of circle = πr2 Circumference of circle = 2πr Perimeter of square = 4a Area of square = a2 According to the question, 2πr = 4a 2 × \(\frac{22}{7}\) × r = 4a \(\frac{44}{7}\) × r = 4a \(\frac{r}{a}\) = \(\frac{7}{11}\) Now the area of circle = πr2 = \(\frac{22}{7}\) × 7 × 7 = 154 The area of square = a2 = 112 = 121 So we can clearly see that Area of the circle > Area of the square |