Practicing Success
Practicing Success
CUET Preparation Today
A magnetic field of 5×10−4T just balances a perpendicular electric field of 15 kV/m in their effect on an electron beam passing through the two fields in a direction perpendicular to both of them. What is the speed of the electrons? |
75 m/s 3×104 m/s 3×107 m/s 3.5 ×103 m/s |
3×107 m/s |
v = \(\frac{E}{B}\) = \(\frac{15 x 10^{3}}{5 x 10^{-4}}\) = 3×107 m/s |
