Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Probability Distributions

Question:

Two statements are given, one labelled Assertion (A) and the other labelled Reason (R).

Assertion (A): If 6 coins are tossed and the random variables X denotes the difference of number of heads and number of tails obtained, then X can take values 0, 2, 4 and 6.

Reason (R): If a random variable X assumes values $x_1, x_2, ..., ..., x_n$ then $P(X = x_1) + P(X = x_2) + ... + P(X = x_n) = 1$.

Select the correct answer from the options given below.

Options:

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).

Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).

Assertion (A) is true, but Reason (R) is false.

Assertion (A) is false, but Reason (R) is true.

Correct Answer:

Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).

Explanation:

The correct answer is Option (2) → Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).

When a coin is tossed 6 times, then

No. of heads

  0  

  1  

  2  

  3  

  4  

  5  

  6  

No. of tails

6

5

4

3

2

1

0

Difference

6

4

2

0

2

4

6

From the above table, we can see that X can take values 0, 2, 4, 6.

∴ Assertion is true.

Also, Reason is true.

Reason is not the correct explanation of Assertion.