The solution of the differential equation $\frac{dy}{dx}=\frac{ax + c}{by + d}$ represents a circle when
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $a =-b$
Given differential equation:
$\frac{dy}{dx} = \frac{ax + c}{by + d}$
Separate variables:
$(by + d) dy = (ax + c) dx$
Integrate both sides:
$\int (by + d)\,dy = \int (ax + c)\,dx$
$\frac{b}{2}y^2 + dy = \frac{a}{2}x^2 + cx + C$
Rewriting:
$\frac{a}{2}x^2 + cx - \frac{b}{2}y^2 - dy + C = 0$
To represent a circle, the general second-degree equation must satisfy:
- Both $x^2$ and $y^2$ terms must be present with equal coefficients.
- No $xy$ term.
In our case, coefficients of $x^2$ and $y^2$ are:
$\frac{a}{2}$ and $-\frac{b}{2}$
For them to be equal (same coefficient and sign):
$\frac{a}{2} = -\frac{b}{2} \Rightarrow a = -b$