In the interval (1, 2), the function f(x) = 2|x - 1| + 3|x - 2| is:

The correct answer is Option (2) → strictly decreasing. ##

$f(x) = 2|x - 1| + 3|x - 2|$

In $(1, 2)$

$f(x) = +2(x - 1) - 3(x - 2)$

$= 2x - 2 - 3x + 6$

$= -x + 4$

$∵f'(x) = -1$

$f'(x) < 0$

$\Rightarrow f(x)$ is strictly decreasing.