A body of mass m is taken from earth surface to the height h equal to radius of earth, the increase in potential energy will be : |
mgR (1/2) mgR 2 mgR (1/4) mgR |
(1/2) mgR |
Work done = (mgh/1 +h/R), If h = R then work done = \(\frac{mgR}{1+(R/R)}\) = \(\frac{1}{2}mgR\) |