Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Work Power Energy

Question:

On a frictionless surface, a block of mass M moving at speed v collides elastically with another block of same mass M which is initially at rest. After collision the first block moves at an angle \(\theta\) to its initial direction and has a speed v/3 . The second blocks speed after the collision is : 

Options:

\(\frac{\sqrt{3}}{2}v\)

\(\frac{2\sqrt{2}}{3}v\)

\(\frac{3}{4}v\)

\(\frac{3}{\sqrt{2}}v\)

Correct Answer:

\(\frac{2\sqrt{2}}{3}v\)

Explanation:

\(\frac{1}{2}Mv^2 = \frac{1}{2}M(\frac{v}{3})^2 + \frac{1}{2}Mv'^2\)

v' = \(\frac{2\sqrt{2}}{3}v\)