In ΔABC, ∠A = 68°. If I is the incentre of the triangle, then the measure of ∠BIC is:
Answer & explanation
Correct answer: option 1
According to the concept
\(\angle\)BIC = \({90}^\circ\) + \(\frac{1}{2}\) x \(\angle\)BAC
\(\angle\)BIC = \({90}^\circ\) + \(\frac{1}{2}\) x \({68}^\circ\)
\(\angle\)BIC = \({90}^\circ\) + \({34}^\circ\)
\(\angle\)BIC = \({124}^\circ\)
Therefore, \(\angle\)BIC is \({124}^\circ\)