Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Probability

Question:

A random  variable X has the following probability distribution where k is some number :

X 0 1 2
P(X) k 2k 3k

Find value of k.

Options:

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{1}{6}$

1

Correct Answer:

$\frac{1}{6}$

Explanation:

The correct answer is Option (3) → $\frac{1}{6}$

$∑p(x_i)=1$

so $K+2K+3K=1$

$6K=1⇒K=\frac{1}{6}$