Solve $|3x-2|≤\frac{1}{2}$.

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

Solve $|3x-2|≤\frac{1}{2}$.

Options:

$[\frac{1}{2},\frac{5}{2}]$

$[-\frac{1}{2},\frac{5}{6}]$

$[\frac{1}{2},\frac{5}{6}]$

$[-\frac{1}{2},-\frac{5}{2}]$

Correct Answer:

$[\frac{1}{2},\frac{5}{6}]$

Explanation:

$|3x-2|≤\frac{1}{2}$

or $-\frac{1}{2}≤3x-2≤\frac{1}{2}$

or $\frac{3}{2}≤3x≤\frac{5}{2}$

or $\frac{1}{2}≤x≤\frac{5}{6}$

or $x∈[\frac{1}{2},\frac{5}{6}]$