What is the electric potential due to a dipole along with its axial position?
Answer & explanation
Correct answer: option 4
$\text{Potential due to a dipole at a point is }V = \frac{p cos\theta}{4\pi\epsilon_0 r^2}$
$\Rightarrow \text{ At axial position }\theta = 0^o \text{ or } 180^o$
$\Rightarrow$ Vaxial = +- \(\frac{p}{4\pi\epsilon_{o}r^{2}}\)