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In a reflecting telescope, the focal length of the eyepiece is 5 cm. What should be the radius of curvature of the objective mirror to have magnifying power of 40? |
1 m 2 m 4 m 8 m |
4 m |
Magnification of reflecting telescope is $M = \frac{f_0}{f_e}$ = $\frac{f_0}{5 cm}$ $⇒ f_0 = 200 cm $ $⇒ R = 2 f_0 = 400 cm = 4m$ |
