CUET Preparation Today
The inverse of the matrix $\left[\begin{array}{cc}2 & -1 \\ 1 & 0\end{array}\right]$ is |
$\left[\begin{array}{cc}2 & -1 \\ 1 & 0\end{array}\right]$ $\left[\begin{array}{ll}-2 & 1 \\ -1 & 0\end{array}\right]$ $\left[\begin{array}{cc}2 & 1 \\ -1 & 0\end{array}\right]$ $\left[\begin{array}{cc}0 & 1 \\ -1 & 2\end{array}\right]$ |
$\left[\begin{array}{cc}0 & 1 \\ -1 & 2\end{array}\right]$ |
The correct answer is Option (4) → $\left[\begin{array}{cc}0 & 1 \\ -1 & 2\end{array}\right]$ |
