For the principal value branch, the value of $\sin\left(\frac{\pi}{2}-\sin^{-1}(-\frac{\sqrt{3}}{2})\right)$ is

$\frac{1}{2}$

The correct answer is Option (3) → $\frac{1}{2}$

Given expression:

$\sin\left(\frac{\pi}{2} - \sin^{-1}\left(-\frac{3}{\sqrt{2}}\right)\right)$

Use identity:

$\sin\left(\frac{\pi}{2} - \theta\right) = \cos\theta$

So,

$= \cos\left(\sin^{-1}\left(-\frac{\sqrt{3}}{2}\right)\right)$

Let $\theta = \sin^{-1}\left(-\frac{\sqrt{3}}{2}\right)$

Then, $\cos(\theta) = \sqrt{1 - \sin^2(\theta)} = \sqrt{1 - \left(-\frac{\sqrt{3}}{2}\right)^2} = \sqrt{1 - \frac{3}{4}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$