If $\begin{bmatrix}a+2 & 3b+2c\\c+3&7d+6\end{bmatrix}=\begin{bmatrix}2 & -3\\3c& -8\end{bmatrix},$ then the values of a, b, c and d are,
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $a=0, b=-2, c=\frac{3}{2}, d=-2$
$\begin{bmatrix}a+2 & 3b+2c\\c+3&7d+6\end{bmatrix}=\begin{bmatrix}2 & -3\\3c& -8\end{bmatrix}$
$⇒a+2=2$
$⇒a=0$
and, $⇒7d+6=-8$
$⇒7d=-14$
$⇒d=-2$
and, $⇒c+3=3c$
$⇒3=2c$
$⇒c=\frac{3}{2}$
and, $3b+2c=-3$
$⇒3b+3=-3$
$⇒3b=-3-3=-6$
$⇒b=-2$