If $y=x^3log\, x,$ then $\frac{d^2y}{dx^2}$ is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $x(5 + 6\log x)$
$y=x^3\log x$
$⇒\frac{dy}{dx}=3x^2\log x+x^2$
$⇒\frac{d^2y}{dx^2}=3(2x\log x+x)+2x$
$=6x\log x+5x$
$=x(6\log x+5)$