The average of 3 digit numbers such that xx0, 26x, xx5, 7x6, 2x1, x32 is 428.  Find the average of x+1, x+3, x+7.

20 \(\frac{17}{3}\) \(\frac{23}{3}\) \(\frac{13}{3}\)

\(\frac{23}{3}\)

Take unit digits of all the numbers: 0 + x + 5 + 6 + 1 + 2 = 8  14 + x = 8 4 + x = 8                                (unit digit of 14 is 4) x = 8 - 4 = 4 Now, average of x+1, x+3, x+7 is = \(\frac{x+1+x+3+x+7}{3}\) = \(\frac{5+7+11}{3}\) = \(\frac{23}{3}\)