If $tan^{-1}x=y,$ then
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $x \in R, y \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$
$\tan^{-1}x=y$
y = range of $\tan^{-1}x=(-\frac{π}{2},\frac{π}{2})$
$x∈R,y∈(-\frac{π}{2},\frac{π}{2})$