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If $f : R \to R$ be the function defined by $f(x) = x^3 + 5$, then $f^{-1}(x)$ is |
$(x + 5)^{\frac{1}{3}}$ $(x - 5)^{\frac{1}{3}}$ $(5 - x)^{\frac{1}{3}}$ $5 - x$ |
$(x - 5)^{\frac{1}{3}}$ |
The correct answer is Option (2) → $(x - 5)^{\frac{1}{3}}$ ## Given that, $f(x) = x^3 + 5$ Let $y = x^3 + 5 \Rightarrow x^3 = y - 5$ $x = (y - 5)^{\frac{1}{3}} \Rightarrow f(x)^{-1} = (x - 5)^{\frac{1}{3}}$ |
