If $f : R \to R$ be the function defined by $f(x) = x^3 + 5$, then $f^{-1}(x)$ is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $(x - 5)^{\frac{1}{3}}$ ##
Given that, $f(x) = x^3 + 5$
Let $y = x^3 + 5 \Rightarrow x^3 = y - 5$
$x = (y - 5)^{\frac{1}{3}} \Rightarrow f(x)^{-1} = (x - 5)^{\frac{1}{3}}$