Phone calls arrive at the rate of 48 per hour at the reservation desk for Indian Airlines. Suppose no calls are currently on hold. If the agent takes 5 minutes to complete the current call, how many do you expect to be waiting by that time? What is the probability that none will be waiting?

Expected number of calls = 4; Probability of no calls waiting = 0.018

The correct answer is Option (1) → Expected number of calls = 4; Probability of no calls waiting = 0.018

Given number of phone calls arrives per hour is 48.

Let random variable X be the number of phone calls in 5 minutes interval of time, then

$λ = 48 ×\frac{5}{60}⇒λ = 4$.

So, we expect that 4 callers will be waiting during that time.

Now, $P(X = 0) =\frac{4^{0}e^{-4}}{0}=0.018$