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The equation of tangent line to $y=2x^2+7$ which is parallel to the line $4x-y+3=0$ is : |
$4x-y+1=0$ $4x-y+5=0$ $x+4y+5=0$ $4x-y+3=0$ |
$4x-y+5=0$ |
$⇒x=1$ from (1) so $y=2×1^2+7=9$ point of contact (1, 9) equation of tangent = $y-9=4(x-1)$ $y-9=4x-4$ so $4x-y+5=0$ |
