Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Two charged metallic spheres with radii $R_1$ and $R_2$ are brought in contact and then separated. The ratio of final charges $Q_1$ and $Q_2$ on the two spheres respectively will be _________.

Fill in the blank with the correct answer from the options given below.

Options:

$\frac{Q_1}{Q_2}=\frac{R_2}{R_1}$

$\frac{Q_1}{Q_2}<\frac{R_1}{R_2}$

$\frac{Q_1}{Q_2}>\frac{R_1}{R_2}$

$\frac{Q_1}{Q_2}=\frac{R_1}{R_2}$

Correct Answer:

$\frac{Q_1}{Q_2}=\frac{R_1}{R_2}$

Explanation:

When two spheres are in contact then their potential become equal.

$ V_1 = V_2 \Rightarrow \frac{kQ_1}{R_1} = \frac{kQ_2}{R_2} \Rightarrow \frac{Q_1}{Q_2} = \frac{R_1}{R_2}$

The correct answer is Option (4) → $\frac{Q_1}{Q_2}=\frac{R_1}{R_2}$