There are 32 consecutive natural numbers. The average of the first 13 numbers is x. What is the average of the next 19 numbers?

x + 16

Sum of first 32 consecutive numbers = \(\frac{n(n+1)}{2}\)

= \(\frac{32 × 33}{2}\) = 528

Average of first 13 numbers = \(\frac(n+1)}{2}\) = \(\frac{14}{2}\) = 7

so x = 7

Sum of 13 numbers = 13 × 7 = 91

Remaining sum of 19 numbers = 528 - 91 = 437

Average of 19 numbers = \(\frac{437}{19}\) = 23

23 = 7 + 17 = x + 16

SO , ans is   x + 16