CUET Preparation Today
Electric potential due to dielectric dipole on equational line at distance r from the centre of the dipole is (P = dipole moment) (assume dipole as very short). |
\(V=±\frac{1}{4πε_0}\frac{P}{r^2}\) \(V=±\frac{1}{4πε_0}\frac{2P}{r^2}\) \(V=±\frac{1}{4πε_0}\frac{P}{r^3}\) V = 0 |
V = 0 |
$\text{The potential due to dipole is given by} V = \frac{Pcos\theta}{4\pi\epsilon_0 r^2} $ $\text{ At equatorial point } \theta = 90^o$ $\Rightarrow V = 0$ |
