The sum of the order and degree of the differential equation $\frac{d^2y}{dx^2}+\sqrt{\frac{dy}{dx}}+(1+x)=0$ is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 4
$\frac{d^2y}{dx^2}+(1+x)=-\sqrt{\frac{dy}{dx}}$
Squaring both side
$\left(\frac{d^2y}{dx^2}\right)^2+(1+x)^2+2\frac{d^2y}{dx^2}(1+x)=\frac{dy}{dx}$
order = 2, degree = 2
So $2+2=4$