Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

A diode having potential difference 0.5 A across its junction which does not depend on current, is connected in series with resistance of 20 Ω across source. If 0.1 A passes through resistance, then what is the voltage of the source?

Options:

1.5 V

2.0 V

2.5 V

5 V

Correct Answer:

2.5 V

Explanation:

Voltage of the source, $V' = V_D + iR = 0.5+ 0.1× 20 = 2.5V$