The decreasing order of value of van't Hoff factor for the following in aqueous medium is

(A) $K_3[Fe(CN)_6]$
(B) $NaCl$
(C) $K_2SO_4$
(D) $C_6H_{12}O_6$

Choose the correct answer from the options given below:

(A), (C), (B), (D)

The correct answer is Option (1) → (A), (C), (B), (D)

1. (A) $K_3[Fe(CN)_6]$ (Potassium ferricyanide)

This is a complex salt that dissociates into three potassium ions and one complex ferricyanide ion:

$K_3[Fe(CN)_6] \rightarrow 3K^+ + [Fe(CN)_6]^{3-}$

• Total particles ($i$): $3 + 1 = \mathbf{4}$

2. (C) $K_2SO_4$ (Potassium sulfate)

This salt dissociates into two potassium ions and one sulfate ion:

$K_2SO_4 \rightarrow 2K^+ + SO_4^{2-}$

• Total particles ($i$): $2 + 1 = \mathbf{3}$

3. (B) $NaCl$ (Sodium chloride)

This salt dissociates into one sodium ion and one chloride ion:

$NaCl \rightarrow Na^+ + Cl^-$

• Total particles ($i$): $1 + 1 = \mathbf{2}$

4. (D) $C_6H_{12}O_6$ (Glucose)

Glucose is a non-electrolyte. It dissolves in water but does not dissociate into ions.

• Total particles ($i$): $\mathbf{1}$

Final Decreasing Order

Comparing the values:

$4 \text{ (A)} > 3 \text{ (C)} > 2 \text{ (B)} > 1 \text{ (D)}$