The conductivity of the centimolar solution of KCl at \(25^0\) C is \(0.210 \text{ ohm}^{–1}\text{ cm}^{–1}\) and the resistance of the cell containing the solution at \(25^0\) C is \(60\) ohm. The value of the cell constant is

\(12.6 \text{ cm}^{–1}\)

The correct answer is OPTION 2 - \(12.6 \text{ cm}^{–1}\)

Relation between conductivity and cell constant:

Cell constant = κ × R

where
κ = conductivity
R = resistance

Given:

κ = 0.210 Ω⁻¹ cm⁻¹
R = 60 Ω

Now,

Cell constant = 0.210 × 60

Cell constant = 12.6 cm⁻¹

The correct answer is Option (2) → 12.6 cm⁻¹.