The conductivity of the centimolar solution of KCl at \(25^0\) C is \(0.210 \text{ ohm}^{–1}\text{ cm}^{–1}\) and the resistance of the cell containing the solution at \(25^0\) C is \(60\) ohm. The value of the cell constant is

\(1.26 \text{ cm}^{–1}\)

Given, Conductivity, \(= 0.210 \text{ ohm}^{–1}\text{ cm}^{–1}\)

Resistsnce\(= 60\text{ohm}\)

Conductance = \(\frac{1}{resistance}\)

We know,

\(\text{Cell constant = }\frac{conductivity}{conductance}\)

\(\text{Cell constant = }\frac{ 0.210 \text{ ohm}^{–1}\text{ cm}^{–1}}{60\text{ohm}}\)

\(\text{Cell constant = }1.257 \text{cm}^{–1}\)

\(\text{Cell constant ≈ }1.26 \text{cm}^{–1}\)