The solution of the differential equation $\frac{d y}{d x}+\sqrt{\frac{1-y^2}{1-x^2}}=0$, is
Answer & explanation
Correct answer: option 2
We have,
$\frac{d y}{d x}+\sqrt{\frac{1-y^2}{1-x^2}}=0 \Rightarrow \frac{1}{\sqrt{1-y^2}} d y+\frac{1}{\sqrt{1-x^2}} d x=0$
On integration, we have
$\sin ^{-1} y+\sin ^{-1} x=+C$