Geeta runs 5/2 times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).
Answer & explanation
Correct answer: option 1
Let speed of Babita = 2S , So , Speed of Geeta = 5S
Let distance travled by Geeta = x m
So , Distance travled by Babita = x - 40
According to question ,
Speed is directly proportional to Distance
\(\frac{2S}{5S}\) = \(\frac{x - 40}{x}\)
2x = 5x - 200
3x = 200
x = \(\frac{200}{3}\) = 66.67m
So , the distance from the starting point where both of them will meet is 66.67 m .