Find the area of the portion of the circle $x^2+y^2=64$ which is exterior to the parabola $y^2 =12x$.
Answer & explanation
Correct answer: option 1
Required Area = $π8^2-2\int\limits_0^A[\sqrt{64-y^2}-\frac{y^2}{12}]dy$
$⇒\frac{16}{3}(8π-\sqrt{3})$
Find the area of the portion of the circle $x^2+y^2=64$ which is exterior to the parabola $y^2 =12x$.
Correct answer: option 1
Required Area = $π8^2-2\int\limits_0^A[\sqrt{64-y^2}-\frac{y^2}{12}]dy$
$⇒\frac{16}{3}(8π-\sqrt{3})$