In a circle centred at O, a tangent AP is drawn from an external point A. If OA = 13 cm and OP = 5 cm, then the length of tangent AP is:
Answer & explanation
Correct answer: option 4
We know that,
(Hypotnuese)2 = (Perpendicular)2 + (Base)2
We have,
OA = 13 cm
OP = 5cm
= (OA)2 = (AP)2 + (OP)2
= 132 = AP2 + 52
= AP = 12 cm