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In a circle centred at O, a tangent AP is drawn from an external point A. If OA = 13 cm and OP = 5 cm, then the length of tangent AP is: |
10 cm 8 cm 18 cm 12 cm |
12 cm |
We know that, (Hypotnuese)2 = (Perpendicular)2 + (Base)2 We have, OA = 13 cm OP = 5cm = (OA)2 = (AP)2 + (OP)2 = 132 = AP2 + 52 = AP = 12 cm |
