A can complete a certain work in 30 days. He started the work. After 4 days, B joined him and the whole work was completed in 10 days from the beginning. B alone can complete one-third of the same work in: |
6 days 3 days 4 days 2 days |
3 days |
A = 30 days, Lets' take A's efficiency as 1, Therefore, total work = 1 x 30 = 30 units, ..(Efficiency × Days = Total work) ⇒ A worked for 4 days = 1 x 4 = 4 units, ⇒ Remaining work = 30 - 4 = 26 units, ⇒ B joined A and they complete 26 units in 6 days = \(\frac{26}{1+B}\) = 6 days, ⇒ B = \(\frac{10}{3}\) (Efficiency) ⇒ Time required by b to complete \(\frac{1}{3}\)rd of the work = \(\frac{1}{3}\) x 30 = \(\frac{10}{10/3}\) = 3 days, ..(\(\frac{Work}{Efficiency}\) = Time) |