If (secθ + cosecθ) = 2\(\sqrt { 2}\) ; 0 < θ < 90°, then value of θ is:
Answer & explanation
Correct answer: option 1
Out of all options when θ = 45° ;
secθ + cosecθ = \(\sqrt { 2}\) + \(\sqrt { 2}\) = 2\(\sqrt { 2}\) satisfies equation
Hence,
θ = 45°