If (secθ + cosecθ) = 2\(\sqr

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If (secθ + cosecθ) = 2\(\sqrt { 2}\) ; 0 < θ < 90°, then value of θ is:

Options:

45°

15°

30°

60°

Correct Answer:

45°

Explanation:

Out of all options when θ = 45° ;

secθ + cosecθ = \(\sqrt { 2}\) + \(\sqrt { 2}\) = 2\(\sqrt { 2}\) satisfies equation

Hence,

θ = 45°