What happens when alkyl chloride is treated with aq. KOH?

Both option 1 and option 2 

The correct answer is option 4. Both option 1 and option 2.

When an alkyl chloride is treated with aqueous potassium hydroxide \((KOH)\), it undergoes a nucleophilic substitution reaction known as hydrolysis. The reaction typically proceeds as follows:

Here is a breakdown of the products:

Alcohol \((ROH)\): The alkyl chloride \((R-Cl)\) reacts with \(KOH\), where the hydroxide ion \((OH^-)\) acts as a nucleophile, attacking the carbon atom bonded to chlorine. This results in the formation of an alcohol \((ROH)\), where \(R\) represents the alkyl group originally bonded to chlorine.

Potassium Chloride \((KCl)\): The chlorine atom is replaced by the hydroxide ion, forming potassium chloride \((KCl)\) as a byproduct.

Conclusion: When alkyl chlorides are treated with aqueous \(KOH\), both an alcohol and potassium chloride are formed. Therefore, the correct answer is: Both option 1 and option 2.

This choice reflects the formation of both alcohol \((ROH)\) and potassium chloride \((KCl)\) as products of the reaction between alkyl chloride and aqueous \(KOH\).