If cotA=\(\frac{15}{8}\) find the value of tan2A.

\(\frac{200}{161}\) \(\frac{240}{161}\) \(\frac{243}{161}\) \(\frac{249}{161}\)

\(\frac{240}{161}\)

= cotA = \(\frac{15}{8}\) = tanA = \(\frac{8}{15}\) Put in → tan2A=\(\frac{2tanA}{1-tan^2A}\) ⇒\(\frac{2×\frac{8}{15}}{1-\frac{64}{225}}\) =\(\frac{16}{15}\)×\(\frac{225}{161}\) = \(\frac{240}{161}\)