The angle between two vectors $\vec{a}$ and $\vec{b}$ with magnitudes $\sqrt{3}$ and 4 respectively and $\vec{a}.\vec{b}=2\sqrt{3}$ is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{\pi}{3}$
$|\vec{a}|=\sqrt{3}$
$|\vec{b}|=4$
$\vec{a}.\vec{b}=2\sqrt{3}$
$|\vec{a}||\vec{b}|\cos θ=\frac{2\sqrt{3}}{4\sqrt{3}}⇒\cos θ=\frac{1}{2}$
$⇒θ=\frac{\pi}{3}$