A compound possesses 8% sulfur by mass. The least molecular mass is:

400

The correct answer is option 2. 400.

We are given a compound that possesses \(8\%\) sulfur by mass. So, if we assume we have \(100 g\) of the compound then it will be having \(8 g\) of sulfur.

Now, we know that the molecular weight of sulfur is \(32 g\).

A compound must contain at least one atom of sulfur because partial atom is not possible. So, we can say one atom of sulfur will be present in the compound.

Hence,

\(8 g\) of sulfur is present in \(100 g\) of the compound

\(1 g\) of sulfur would be present in \(\frac{100}{8}\) g of the compound

Then, \(32 g\) of sulfur will be present in, \(\frac{100}{8} x 32 = 400 g\) of the compound.

Therefore, we can conclude that the correct answer to this question is option 2.