The ratio of the areas between the curves = cos x and y = cos 2x and x-axis from x = 0 to x = $\frac{\pi}{3}$ is |
1 : 3 2 : 1 $\sqrt{3}$ : 1 None of these |
2 : 1 |
$A_1=\int\limits_0^{\pi / 3} \cos x d x=\frac{\sqrt{3}}{2}$ $A_2=\int\limits_0^{\pi / 2} \cos 2 x d x=\frac{\sqrt{3}}{4}$ ∴ $\frac{A_1}{A_2}=\frac{2}{1}$ Hence (2) is the correct answer. |