Let x denotes the number of heads in a simultaneous toss of three coins, then $P(0 < x ≤3)$

$\frac{7}{8}$

The correct answer is Option (3) → $\frac{7}{8}$

Sample space for 3 coins → total outcomes = 8.

Possible values of $x$ (number of heads): 0, 1, 2, 3.

$P(0 < x \le 3)$ means $P(x = 1 \text{ or } 2 \text{ or } 3)$.

$P(x = 1) = \frac{3}{8},\; P(x = 2) = \frac{3}{8},\; P(x = 3) = \frac{1}{8}$

Hence, $P(0 < x \le 3) = \frac{3 + 3 + 1}{8} = \frac{7}{8}$

Final Answer: $\frac{7}{8}$