If x² - \(\sqrt[2]{10}\)x + 1 = 0, then find x - \(\frac{1}{x}\)

\(\sqrt {6}\) 

Formula → [If x + \(\frac{1}{x}\) = M, x - \(\frac{1}{x}\) = \(\sqrt {M^2 - 4}\)]

x² - \(\sqrt[2]{10}\)x + 1 = 0

x² + 1 = \(\sqrt[2]{10}\)x

x + \(\frac{1}{x}\) = \(\sqrt[2]{10}\)

x - \(\frac{1}{x}\) = \(\sqrt {(\sqrt[2]{10})^2 - 4}\)

x - \(\frac{1}{x}\) = \(\sqrt {6}\)