$6\sin^{-1}(x^2-6x+8.5)=π$ if:
Answer & explanation
Correct answer: option 4
$6\sin^{-1}(x^2-6x+8.5)=\frac{π}{6}⇒x^2-6x+8.5=\sin\frac{π}{6}⇒(x-4)(x-2)=0$
$6\sin^{-1}(x^2-6x+8.5)=π$ if:
Correct answer: option 4
$6\sin^{-1}(x^2-6x+8.5)=\frac{π}{6}⇒x^2-6x+8.5=\sin\frac{π}{6}⇒(x-4)(x-2)=0$