$6\sin^{-1}(x^2-6x+8.5)=π$ if:

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

$6\sin^{-1}(x^2-6x+8.5)=π$ if:

Options:

x = 1, 2

x = 2, 3

x = 3, 4

x = 4, 2

Correct Answer:

x = 4, 2

Explanation:

$6\sin^{-1}(x^2-6x+8.5)=\frac{π}{6}⇒x^2-6x+8.5=\sin\frac{π}{6}⇒(x-4)(x-2)=0$