CUET Preparation Today
CUET
-- Mathematics - Section B1
Inverse Trigonometric Functions
$6\sin^{-1}(x^2-6x+8.5)=π$ if:
x = 1, 2
x = 2, 3
x = 3, 4
x = 4, 2
$6\sin^{-1}(x^2-6x+8.5)=\frac{π}{6}⇒x^2-6x+8.5=\sin\frac{π}{6}⇒(x-4)(x-2)=0$
