Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

The dimensional formula of coefficient of viscosity is

Options:

$[MLT^{-1}]$

$[M^{-1}L^2T^{-2}]$

$[ML^{-1}T^{-1}]$

none of these

Correct Answer:

$[ML^{-1}T^{-1}]$

Explanation:

F = 6$\pi\eta$ vr

$[\eta]=\frac{[F]}{[vr]}=\frac{[MLT^{-2}]}{[LT^{-1}][L]}=[ML^{-1}T^{-1}]$