Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Charge Q is given to the upper plate of an isolated parallel plate capacitor of capacitance C. The potential difference between the plates

Options:

$\frac{Q}{C}$

$\frac{Q}{C/2}$

$\frac{Q/2}{C}$

Zero

Correct Answer:

$\frac{Q/2}{C}$

Explanation:

In general, for charge Q­1 and Q2on upper and lower plate respectively the charge distributions on outer and inner part of the plates are shown in figure.

                        Here Q­1 =Q,  Q2 = 0

\                     Charge on inner side of plate are $\frac{Q}{2}$ and $\frac{-Q}{2}$  respectively.

                        $\text{Hence } V = \frac{Q}{2C}$