CUET Preparation Today
If $2 \sin 2θ-\sqrt{3}$, where $0≤ 2θ ≤90°$, then find the value of $\cos 3θ$ |
0 1 $\frac{\sqrt{3}}{2}$ $\frac{1}{2}$ |
0 |
$2 \sin 2θ-\sqrt{3}$ $ \sin 2θ=\sqrt{3}/2$ sin2θ=sin60∘ θ = 30 3θ = 90 $\cos 3θ$ = $\cos 90$ = 0 The correct answer is Option (1) → 0 |
