Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If $2 \sin 2θ-\sqrt{3}$, where $0≤ 2θ ≤90°$, then find the value of $\cos 3θ$

Options:

0

1

$\frac{\sqrt{3}}{2}$

$\frac{1}{2}$

Correct Answer:

0

Explanation:

$2 \sin 2θ-\sqrt{3}$

$ \sin 2θ=\sqrt{3}/2$ 

sin2θ=sin60∘

θ = 30

3θ = 90

$\cos 3θ$ = $\cos 90$ = 0

The correct answer is Option (1) → 0