Practicing Success
Practicing Success
CUET Preparation Today
If in a binomial distribution n = 4, P(X = 0) = $\frac{16}{81}$, then P(X = 4) equals: |
$\frac{1}{16}$ $\frac{1}{81}$ $\frac{1}{27}$ $\frac{1}{8}$ |
$\frac{1}{81}$ |
The correct answer is Option (2) - $\frac{1}{81}$ $P(X = 0) = \frac{16}{81}$ so ${^4C}_0×P^0(1-P)^4=\frac{16}{81}$ $1-P=\frac{2}{3}⇒P=\frac{1}{3}$ $P(X = 4) ={^4C}_4P^4(1-P)^0=\frac{1}{81}$ |
