If in a binomial distribution n = 4, P(X = 0) = $\frac{16}{81}$, then P(X = 4) equals:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) - $\frac{1}{81}$
$P(X = 0) = \frac{16}{81}$
so ${^4C}_0×P^0(1-P)^4=\frac{16}{81}$
$1-P=\frac{2}{3}⇒P=\frac{1}{3}$
$P(X = 4) ={^4C}_4P^4(1-P)^0=\frac{1}{81}$