If P and Q are non-singular square matrices of the same order, then $(PQ^{-1})^{-1}$ equals
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $QP^{-1}$
Given: $P$ and $Q$ are non-singular square matrices
We need: $(PQ^{-1})^{-1}$
Use property: $(AB)^{-1} = B^{-1} A^{-1}$
$(PQ^{-1})^{-1} = (Q^{-1})^{-1} P^{-1} = Q P^{-1}$