CUET Preparation Today
Which of the following shows the correct relation between electric Intensity E, and electric potential V: |
$V=\frac{d E}{d r}$ $E=\frac{d V}{d r}$ $E=\frac{-dV}{dr}$ $V=\frac{-dE}{dr}$ |
$E=\frac{-dV}{dr}$ |
The correct answer is Option (3) → $E=\frac{-dV}{dr}$ |
