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Home Questions QU8JEY2XKD

Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

Maximum speed of emitted electron is

$V_{max} = \sqrt{2\frac {h\nu - \phi}{m}}$

$\Rightarrow \frac{V_1}{V_2} = \sqrt{\frac{1 - 0.5}{2.5 - 0.5}} = \frac{1}{2}$

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