A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 4V and then adiabatically to a volume 32V. The final pressure of the gas is : (take \(\gamma = \frac{5}{3}\))
Answer & explanation
Correct answer: option 2
For isothermal process : PV = constant
PoV = P'(4V)
⇒ P' = \(\frac{P_o}{4}\)
For adiabatic process : PV\(\gamma\) = constant
P'(4V)\(\gamma\) = P'' (32V)\(\gamma\)
For monoatomic gas : \(\gamma = \frac{5}{3}\)
P'' = Po/128